Appendix B ZGNR Optical Matrix Elements
B.1 Bloch Wave Functions Prefactors
To obtain CA and CB in Eq. 18, one can substitute Eq. 6 and Eq. 19 into the Shrödinger equation H|ψ⟩=E|ψ⟩. Considering an A-type carbon atom at some atomic site n, and its three nearest neighbors, the Hamiltonian can be written as:
H = t | BN−n+1⟩ ⟨ An | +
t | BN−n+1′⟩ ⟨ An | +
t | BN−n⟩ ⟨ An |.
(1) |
Using Eq. 1 along with the wave functions obtained in Eq. 12, one obtains:
| ECA ei kx xnAsin(n θ) = | tCBei kx xN−n+1Bsin((N−n+1)θ) |
| +tCBei kx xN−n+1B′sin((N−n+1)θ) |
| +tCBei kx xN−nBsin((N−n)θ).
|
|
(2) |
Therefore, the relation between CA and CB can be written as:
| ECAsin(nθ) | |
| sin | ⎛
⎝ | (N−n+1)θ | ⎞
⎠ | +e | | sin | ⎛
⎝ | (N−n)θ | ⎞
⎠ | | ⎤
⎥
⎦ |
|
| =
tCB | ⎡
⎢
⎢
⎣ | 2 cos | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | sin((N−n+1)θ)+sin((N−n)θ) | ⎤
⎥
⎥
⎦ | .
|
|
|
(3) |
By employing the relation sin(x)sin(y)=(1/2)[cos(x−y)−cos(x+y)] and using Eq. 22,
Analogously, for the N−n+1th B-type carbon atom one can obtain the following relation:
|
ECB sin | ⎛
⎝ | ⎛
⎝ | N−n+1 | ⎞
⎠ | θ | ⎞
⎠ | = tCA | ⎡
⎢
⎢
⎣ | 2 cos | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | sin(nθ) + sin((n−1)θ) | ⎤
⎥
⎥
⎦ |
|
(5) |
which gives
From Eq. 4 and Eq. 6, one can find that CA=± CB.
Also, the dispersion relation can be found by multiplying Eq. 3 by Eq. 5,
| E2CACB sin(nθ) | sin((N−n+1)θ) |
| =
t2CACB | ⎡
⎢
⎢
⎢
⎣ | 4cos2 | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | sin((N−n+1)θ)sin(nθ) |
|
| +2cos | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | sin((N−n+1)θ)sin((n−1)θ) |
|
| +2cos | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | sin((N−n)θ) sin(nθ) |
|
| +sin((N−n)θ) sin((n−1)θ) | ⎤
⎥
⎥
⎥
⎦ | .
|
|
|
(7) |
With the help of trigonometric identities and Eq. 22, this expression can be reformatted as
|
E = ± t | ⎡
⎢
⎢
⎣ | 1+4cos2 | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | +4cos | ⎛
⎜
⎜
⎝ | | kx acc | ⎞
⎟
⎟
⎠ | cos | ⎛
⎝ | θ | ⎞
⎠ | ⎤
⎥
⎥
⎦ | |
| .
(8) |
B.2 Transverse Wave Functions Amplitude
To solve the recursive formula,
one can consider the ansatz φn=tn and follow similar equation,
This equation is the generating polynomial of the recursive formula 9.
The roots of 10 are
The general solution of the difference equation is
since t1 is a root of the equation, the other root t2 can be written as: t2=t1−1.
By substituting those two roots in 12 one obtains
Imposing the initial condition φ0=0 results in
and from the 13,
We obtain
By substituting 11 and 16 in 15, one obtains
φn= | | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | | − | | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | | .
(17) |
17 can be rewritten as
φn= | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | | − | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | |
|
|
|
|
φ1.
(18) |
B.3 Optical Matrix Elements
Using Eq. 12 and Eq. 13 the matrix elements
pθ,θ′(kx) ≡ ⟨ +, θ, kx| px | −, θ′, kx⟩ for
an interband transition from a valence band state | −, θ, kx⟩ to a
conduction band state | +, θ′, kx⟩ are obtained as
Pθ,θ′=(xθ′−xθ) | | ⟨ θ | H | θ′ ⟩
(19) |
| | ei k (xmB − xnA) sin(nθ) sin(m θ ′) ⟨ An | H | Bm ⟩ (xmB − xnA)
|
| − ei k (xmA − xnB) sin(nθ ′) sin(mθ) ⟨ Bn | H | Am ⟩ (xmA − xnB) | ⎤
⎥
⎥
⎥
⎦ | .
|
|
|
(20) |
Considering only the nearest neighbors, each atom with some index n has two neighbors with index N−n+1 and one neighbor with index N−n, see Fig. 4.1. Therefore, the index m has only three values with ⟨ An | H | Bm ⟩ = t. So we have
| Pθ,θ′= | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | ⎛
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎠ | | ⎡
⎢
⎢
⎢
⎣ | ⎛
⎜
⎝ | e | | −e | | ⎞
⎟
⎠ | sin(nθ) sin((N−n+1) θ ′) |
|
| − | ⎛
⎜
⎝ | e | | −e | | ⎞
⎟
⎠ | sin(nθ ′) sin((N−n+1)θ) | ⎤
⎥
⎥
⎥
⎦ | ,
|
|
|
(21) |
after some algebra and replacing Ω from Eq. 16, the optical matrix elements are
| Pθ,θ′= | | sin | ⎛
⎜
⎜
⎝ | | kacc | ⎞
⎟
⎟
⎠ |
| | ⎡
⎢
⎢
⎢
⎣ | sin(nθ)sin((N−n+1) θ ′)− |
|
sin(nθ ′)sin((N−n+1)θ) | ⎤
⎥
⎥
⎥
⎦ | .
|
|
|
(22) |